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if string.sub(txt, 1,5) == "!ban" then
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Scripts How work the string.sub numbers
How work the string.sub numbers
4 replies
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1 > ! & 2 > b & 3 > a & 4 > n
so its true > if string.sub(txt, 1,4) == "!ban" then
maybe you want use space after !ban . i mean if you use "!ban " insteat "!ban" then > if string.sub(txt, 1,5) == "!ban " then < is true
example :
if string.sub(txt, 1,5) == "!ban " then
pl=(math.floor(string.sub(txt,6,7)))
parse('banip '..pl)
end
now you can use !ban <id> for ban someone
princeofpersia: example :
as far as I know it is true
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if string.sub(txt, 1, 5) == "!ban" then local adam = string.sub(txt, 7, 8)
but if
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if string.sub(txt, 1, 10) == "!ban" then
local adam = string.sub(txt, 12, 13)
parse("banname "..adam)
return 1
end
elseif string.sub(txt, 1, 2) == "!kick" then
local adam = string.sub(txt, 4, 5)
parse("kick"..adam)
return 1
elseif string.sub(txt, 1, 7) == "!makect" then
local adam 0 string.sub(txt, 9, 10)
parse("makect"..adam)
return 1
end
does such excessive and irregular numbers prevent it from functioning?
this word : slap > we have here 4 letters and with sign ! it's 5
so the strin.sub(1"the first postion in ur cmd","your word letters number")
the commands is !slap
positions are : (1,5) => !(1) , s(2) , l(3) , a(4) , p(5)
then after !slap it will be a space (space's positionis 6) then
id comes after the space and it might be 2 numbers because the maxplayers are 32 then id position is i(7) and d(8)
so the code will be like this
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if string.sub(txt,1,5)=="!slap" then
local kid = tonumber(string.sub(txt,7,8))
parse("slap "..kid)
msg2(id, player(kid,"name").." is slaped")
return 1
end
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