Off Topic Little Endian testing in C
Little Endian testing in C
1 
Offline#include <stdio.h>
#include <stdbool.h>
const bool __LITTLE_ENDIAN__ = ( 0x00FF > 0x0100 );
int main(void){
printf("%d",__LITTLE_ENDIAN__);
}
#include <stdio.h>
int main(void)
{
int i = 1;
char *p = (char *) &i;
if ( p[0] == 1 )
printf("Little Endian\n");
else
printf("Big Endian\n");
return 0;
}
How could they convert it into the machines endianness?? Evil. Pure evil.
const int i = 1; #define is_bigendian() ((*(char*)&i)==0)
DannyDeth has written#include <stdio.h>
#include <stdint.h>
int main(void){
uint16_t shr = 1;
if( ((shr >> 8) & 0x00FF) == 0x01) {
printf("Little Endian\n");
} else {
printf("Big Endian\n");
}
}
1