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Lua error !!

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Lua error !!

2 Antworten

Lua error !!

Jhony
User Off

Offline

05.10.12 22:36:35

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addhook("second","ekip")
function ekip(id)
if player(id,"team") == 1 then
for l = 1,49 do
parse("strip "..l)
end
for v = 52,59 do
parse("strip "..v)
end
for y = 61,68 do
parse("strip "..y)
end
for x = 74,81 do
for i = 1,32 do
parse("strip "..x)
parse("strip "..i.." 84")
parse("strip "..i.." 86")
parse("strip "..i.." 87")
parse("strip "..i.." 89")
parse("strip "..i.." 90")
parse("strip "..i.." 91")
parse("strip "..i.." 92")
return l,v,y,x,i,1
end
end
if player(id,"team") == 2 then
parse("strip "..i.." 85")
parse("strip "..i.." 83")
parse("strip "..i.." 69")
parse("strip "..i.." 60")
parse("strip "..i.." 72")
return i,1
end
end
end

fix please

LUA ERROR: sys/lua/yyy.lua:1528: bad argument #1 to 'player' (number expected, got nil)

Re: Lua error !!

Yates
Reviewer Off

Offline

05.10.12 22:39:18

The second hook does not have an id parameter.

if player(id,"team") == 1 then

Will not work.

And tab your code for fuck sake.

Re: Lua error !!

Powermonger
User Off

Offline

06.10.12 20:24:06

So if I understood correctly, you want players only use weapons 50, 51, 60, 69, 70, 71, 72 and 73 right?
And if player is using something else, it will be stripped.

If thats true, you should try select hook:

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addhook("select","ekip")
function ekip(id)
local p = player(id,"weapontype")
	if p ~= 50 or p ~= 51 or p ~= 60 or p ~= 69 or p ~= 70 or p ~= 71 or p ~= 72 or p ~= 73 then
		parse("strip "..id.." "..p)
	end
end

Works?

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