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Found a way; nvm ;3
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string.format('%.2f', value)
edited 4×, last 20.04.12 07:44:19 am
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Scripts Round to 2 numbers after comma
Round to 2 numbers after comma
13 replies
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Found a way; nvm ;3
OWait if I'm not wrong, but probably I am...
Try to use <wholespamnumber> % 0.10
Infinite Rain has writtenWhut.
Useless comments are useless. He wants to round numbers to two after the comma.
@
Alistaire: No idea, but shouldn't "9213.92" be 9213.93 instead as you're rounding up. Avo has writtenYou mean 9213.928~9213.3 ??
No. I mean I want a function.
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function round(num)
local a = math.floor(num*100 + 0.5)/ 100
return a,string.format("%.2f",a)
end
num,num_rep = round(9213.001)
print(num,num_rep)
output:
9213 9213.00
here you go..
it depends on what you want as a return from the function, a string, use the string.format. a number, use the normal a.
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function round(nmb,count) if not count then count=2 end local nmb2=math.floor(nmb) local number=nmb-nmb2 number=nmb2*math.power(10,count) number=math.floor(number) number=number/math.power(10,count) nmb2=nmb2+number return nmb2 end
i think it should work, else do it this way but change logical bugs(if there is any)
*EDITED*
edited 1×, last 19.04.12 10:29:39 pm
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string.format('&.2f', value)
Alistaire has writtenI've found a much easier way;
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string.format('&.2f', value)
You mean I found it? because you just copied what i had.
My code rounds the number ( something you asked for) and plain %.2f just shortens the amount of digits..
Snurq has written Alistaire has writtenI've found a much easier way;
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string.format('&.2f', value)
You mean I found it? because you just copied what i had.
My code rounds the number ( something you asked for) and plain %.2f just shortens the amount of digits..
Oh for fuck's sake. You can find printf/string.format examples anywhere.
Re-re edit: string.format("%.2f",x) also rounds up if the next digit is >= 5
edited 4×, last 19.04.12 11:37:42 pm
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function round(nmb,count) if not count then count=2 end local nmb2=math.floor(nmb) local number=nmb-nmb2 number=nmb2*math.power(10,count) number=math.floor(number) number=number/math.power(10,count) nmb2=nmb2+number return nmb2 end
i think it should work, else do it this way but change logical bugs(if there is any)
*EDITED*
Are you aware that wrote shit?
Yates has written@ Alistaire: No idea, but shouldn't "9213.92" be 9213.93 instead as you're rounding up.
Alistaire: No idea, but shouldn't "9213.92" be 9213.93 instead as you're rounding up.math.floor always rounds down.
Snurq has writtenbecause you just copied what i had.
I've searched it around the internet and found it in the Lua Dictionary.
I didn't even notice your script.
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